A linear equation in two variables is an equation of the form ax + by + c = 0, where a, b, and c are real numbers and a and b are not both zero. A single such equation has infinitely many solutions, as each solution (x, y) corresponds to a point lying on a straight line. This chapter studies what happens when we consider two such equations together, that is, a pair of linear equations, and how to find their common solutions.
The pair of equations represents two straight lines in the plane. Their common solution is the point where the two lines intersect, if they do. Depending on the relative position of the lines, a system may have a unique solution, infinitely many solutions, or no solution at all. These three cases correspond to intersecting lines, coincident lines, and parallel lines respectively.
This chapter equips students with three algebraic methods to solve such systems: the substitution method, the elimination method, and the cross-multiplication method. These methods are used not only to solve pure mathematical problems but also to model and solve word problems involving ages, numbers, speeds, and mixtures, which form a significant part of the board examination.
Consider the pair a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0.
The lines intersect at exactly one point if: a1/a2 is not equal to b1/b2
The lines coincide if: a1/a2 = b1/b2 = c1/c2
The lines are parallel and distinct if: a1/a2 = b1/b2 is not equal to c1/c2
A pair of linear equations is said to be consistent if it has at least one solution (Cases 1 and 2) and inconsistent if it has no solution (Case 3).
Example: Solve x + y = 5 and x - y = 1. From the first, y = 5 - x. Substituting into the second: x - (5 - x) = 1, so 2x - 5 = 1, x = 3. Then y = 2. Hence the solution is x = 3, y = 2.
The substitution method is especially convenient when one of the coefficients of a variable is 1, making the substitution straightforward.
Example: Solve 3x + 2y = 11 and 2x + 3y = 4. Multiply the first by 2 and the second by 3: 6x + 4y = 22 and 6x + 9y = 12. Subtracting: -5y = 10, so y = -2. Then 3x - 4 = 11, so x = 5. Solution: x = 5, y = -2.
The elimination method is systematic and works well even when coefficients are not simple.
For the system a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0, the solution is given by: x/(b1c2 - b2c1) = y/(c1a2 - c2a1) = 1/(a1b2 - a2b1)
Provided a1b2 - a2b1 is not zero. Equivalently: x = (b1c2 - b2c1)/(a1b2 - a2b1) y = (c1a2 - c2a1)/(a1b2 - a2b1)
The denominator a1b2 - a2b1 vanishes precisely when the lines are parallel or coincident, which is the same condition as a1/a2 = b1/b2.
Write the coefficients in the array a1 b1 c1 / a2 b2 c2. Then x numerator = b1c2 - b2c1, y numerator = c1a2 - c2a1, and common denominator = a1b2 - a2b1, taking care with signs.
Some equations that do not look linear can be reduced to linear form by substitution. For example, the pair: 1/x + 1/y = 7 and 2/x + 3/y = 17 can be solved by letting u = 1/x and v = 1/y, giving the linear system u + v = 7 and 2u + 3v = 17.
Solving: multiply the first by 2 to get 2u + 2v = 14; subtract from the second: v = 3, then u = 4. Hence 1/x = 4 and 1/y = 3, so x = 1/4 and y = 1/3.
This technique is frequently applied to word problems involving reciprocals of quantities such as speeds of boats and streams or the time taken to do a piece of work.
Word problems translate real situations into a pair of linear equations. The steps are:
Common contexts include ages, sums of digits of numbers, speed and distance, money and tickets, and mixing of solutions. Correct framing of equations is the most important skill tested here, and full marks usually depend on both the equations and the final verified answer.
| Case | Condition | Type of Lines | Solutions | Consistency |
|---|---|---|---|---|
| a1/a2 != b1/b2 | a1/a2 not equal to b1/b2 | Intersecting | Unique solution | Consistent |
| a1/a2 = b1/b2 = c1/c2 | All ratios equal | Coincident | Infinitely many | Consistent |
| a1/a2 = b1/b2 != c1/c2 | First two ratios equal | Parallel | No solution | Inconsistent |
| Method | Best Used When | Key Idea |
|---|---|---|
| Substitution | A variable has coefficient 1 | Express one variable and substitute |
| Elimination | Coefficients are easy to balance | Make coefficients equal and add/subtract |
| Cross-multiplication | Asked directly or no convenient coefficient | Direct formula using determinant-like cross product |
A pair of linear equations in two variables is a central topic that connects geometry and algebra. Understanding the conditions for intersecting, coincident, and parallel lines gives students an intuitive geometric feel for systems of equations, while the three algebraic methods provide reliable tools for computation. This chapter teaches a general problem-solving strategy of framing equations from real-world situations and solving them systematically, a skill that extends far beyond mathematics. Together with its frequent appearance in board exams, it lays the groundwork for linear programming and systems of equations studied in higher classes.