Integration is the inverse operation of differentiation. If differentiation finds the rate of change of a function, integration reconstructs the function from its rate of change, and simultaneously computes the area enclosed by a curve. The Fundamental Theorem of Calculus unifies these two viewpoints: the definite integral is the net area under a curve, and it can be evaluated by antidifferentiation.
This chapter introduces integration as the inverse of differentiation, presents the standard formulae for indefinite integrals, and develops the three central techniques: integration by substitution, integration by partial fractions, and integration by parts. It then defines the definite integral as the limit of a sum, establishes its properties, and applies the fundamental theorem to evaluate definite integrals. The chapter closes with the reduction-based evaluation of some special definite integrals.
Integration is the most computation-heavy chapter of the syllabus and carries a very high weightage in the board examination. The ability to recognise the form of an integrand and select the right technique quickly is the difference between a good and an excellent performance. The techniques developed here also feed directly into the chapter on application of integrals, where definite integrals are used to compute areas and volumes.
If $\frac{d}{dx}F(x) = f(x)$, then $\int f(x)\,dx = F(x) + C$, where C is the constant of integration. The constant appears because differentiation destroys constants; it is the reason every indefinite integral carries a + C.
$$\int x^n dx = \frac{x^{n+1}}{n+1} + C \quad (n \neq -1), \qquad \int \frac{1}{x} dx = \ln|x| + C$$
$$\int e^x dx = e^x + C, \qquad \int \sin x\, dx = -\cos x + C, \qquad \int \cos x\, dx = \sin x + C$$
$$\int \sec^2 x\, dx = \tan x + C, \qquad \int \sec x \tan x\, dx = \sec x + C$$
$$\int \csc^2 x\, dx = -\cot x + C, \qquad \int \csc x \cot x\, dx = -\csc x + C$$
$$\int \frac{1}{\sqrt{1 - x^2}} dx = \sin^{-1}x + C, \qquad \int \frac{1}{1 + x^2} dx = \tan^{-1}x + C$$
The substitution method reverses the chain rule. If an integrand contains a function and its derivative (up to a constant factor), substitute $t = f(x)$, so that $dt = f'(x)dx$:
$$\int f'(x) \cdot g(f(x))\, dx = \int g(t)\, dt$$
$$\int \frac{f'(x)}{f(x)} dx = \ln|f(x)| + C$$
$$\int [f(x)]^n f'(x) dx = \frac{[f(x)]^{n+1}}{n+1} + C$$
$$\int \frac{f'(x)}{\sqrt{1 - (f(x))^2}} dx = \sin^{-1}(f(x)) + C$$
Common substitutions for trigonometric and radical expressions: $x = a\sin\theta$ for $\sqrt{a^2 - x^2}$, $x = a\tan\theta$ for $\sqrt{a^2 + x^2}$, and $x = a\sec\theta$ for $\sqrt{x^2 - a^2}$.
A rational function $\frac{P(x)}{Q(x)}$, where the degree of P is less than the degree of Q, can be decomposed into partial fractions whose integrals are logarithms:
| Form of denominator | Partial fraction decomposition |
|---|---|
| (x - a)(x - b) | A/(x - a) + B/(x - b) |
| (x - a)^2 | A/(x - a) + B/(x - a)^2 |
| (x - a)(x^2 + px + q) | A/(x - a) + (Bx + C)/(x^2 + px + q) |
For example:
$$\int \frac{1}{(x-1)(x-2)} dx$$
Decompose: $\frac{1}{(x-1)(x-2)} = \frac{A}{x-1} + \frac{B}{x-2}$. Solving gives $1 = A(x-2) + B(x-1)$; substituting x = 1 gives A = -1, and x = 2 gives B = 1. Hence
$$\int \frac{1}{(x-1)(x-2)} dx = -\ln|x-1| + \ln|x-2| + C = \ln\left|\frac{x-2}{x-1}\right| + C$$
The product rule in reverse gives
$$\int u\, dv = uv - \int v\, du$$
The function u is chosen according to the ILATE rule, in order of priority: Inverse trigonometric, Logarithmic, Algebraic, Trigonometric, Exponential. The more complex function should usually be kept as u.
For $\int e^x [f(x) + f'(x)] dx = e^x f(x) + C$, a very useful shortcut.
$$\int x e^x dx = x e^x - \int e^x dx = x e^x - e^x + C = e^x(x - 1) + C$$
$$\int x \ln x\, dx = \frac{x^2}{2}\ln x - \int \frac{x^2}{2} \cdot \frac{1}{x} dx = \frac{x^2}{2}\ln x - \frac{x^2}{4} + C$$
The following integrals occur repeatedly and should be memorised, where a > 0:
$$\int \frac{dx}{a^2 + x^2} = \frac{1}{a}\tan^{-1}\left(\frac{x}{a}\right) + C, \qquad \int \frac{dx}{x^2 - a^2} = \frac{1}{2a}\ln\left|\frac{x-a}{x+a}\right| + C$$
$$\int \frac{dx}{a^2 - x^2} = \frac{1}{2a}\ln\left|\frac{a+x}{a-x}\right| + C, \qquad \int \frac{dx}{\sqrt{a^2 - x^2}} = \sin^{-1}\left(\frac{x}{a}\right) + C$$
$$\int \frac{dx}{\sqrt{x^2 + a^2}} = \ln|x + \sqrt{x^2 + a^2}| + C, \qquad \int \frac{dx}{\sqrt{x^2 - a^2}} = \ln|x + \sqrt{x^2 - a^2}| + C$$
If f is continuous on [a, b] and F is an antiderivative of f, then
$$\int_a^b f(x)\, dx = F(b) - F(a)$$
The even/odd property is a powerful simplification tool: integrals of odd functions over symmetric intervals are automatically zero.
| Integrand | Integral |
|---|---|
| x^n | x^(n+1)/(n+1) + C |
| 1/x | ln |
| e^x | e^x + C |
| sin x | -cos x + C |
| cos x | sin x + C |
| sec^2 x | tan x + C |
| 1/sqrt(1 - x^2) | sin^(-1)x + C |
| 1/(1 + x^2) | tan^(-1)x + C |
| Technique | When to use | Example form |
|---|---|---|
| Substitution | Integrand contains f and f' | integral f'(x)[f(x)]^n dx |
| Partial fractions | Rational function P(x)/Q(x) | integral dx/((x-a)(x-b)) |
| By parts | Product of unlike functions | integral x e^x dx, x ln x dx |
| ILATE | Choice of u in by parts | I, L, A, T, E priority |
| Property | Formula |
|---|---|
| Swap limits | int_a^b f = -int_b^a f |
| Split interval | int_a^b f = int_a^c f + int_c^b f |
| Shift | int_0^a f(x) = int_0^a f(a - x) |
| Even function | int_(-a)^a f = 2 int_0^a f |
| Odd function | int_(-a)^a f = 0 |
Integration transforms the abstract idea of the anti-derivative into one of the most powerful computational tools in mathematics. The indefinite integral reconstructs functions from their rates of change, the substitution method and partial fractions and integration by parts provide systematic techniques for almost every standard integrand, and the definite integral supplies the area under a curve with the fundamental theorem linking the two worlds. The properties of definite integrals, especially the even-odd and shift properties, offer elegant shortcuts that save substantial time in examinations. Because integration threads through the application of integrals, differential equations, and beyond into physics and engineering, this chapter is rightly regarded as the heart of the calculus course. Diligent practice of recognising forms and choosing techniques is the surest route to mastery and to strong examination performance.