Comprehensive theory, key formulas, diagrams, and memory aids for Constructions.
Construction in geometry means drawing figures accurately using only two instruments: a compass and a straightedge (an unmarked ruler). No measurements with a marked ruler or protractor are allowed in the strictest sense, except for copying given lengths. The art of construction teaches us precision, neatness and logical sequencing, because each construction follows a fixed order of steps that must be performed correctly.
In earlier classes we learnt basic constructions like drawing perpendicular bisectors, angle bisectors and angles of known measure. In this chapter we will build on those skills. We will construct the perpendicular bisector of a line segment, the bisector of a given angle, and angles of 60, 90 and 45 degrees. We will also learn to divide a line segment in a given ratio using the internal bisector method and the parallel line method, and to construct triangles when different combinations of sides and angles are given.
To draw the perpendicular bisector of segment AB: 1. Open the compass to a radius more than half of AB. 2. Draw arcs with this radius, centred at A, above and below the line. 3. Draw arcs with the same radius, centred at B, intersecting the earlier arcs. 4. Join the two intersection points. This line is the perpendicular bisector of AB, and its intersection with AB is the midpoint of AB.
To bisect angle ABC: 1. With centre B and any convenient radius, draw an arc cutting BA and BC at P and Q. 2. With centre P and radius more than half of PQ, draw an arc. 3. With centre Q and the same radius, draw another arc intersecting the previous one at R. 4. Join B to R. The ray BR bisects angle ABC.
This construction uses the principle of the basic proportionality theorem (Thales theorem): a line parallel to one side of a triangle divides the other two sides in the same ratio.
We can construct a triangle when the following data are given:
A special construction exists when we are given the base BC, the base angle B, and the sum AB + AC of the other two sides. We construct the triangle as follows: 1. Draw the base BC and construct the given angle at B. 2. On the ray of this angle, mark a point D such that BD = AB + AC. 3. Join D to C and draw the perpendicular bisector of DC. 4. The perpendicular bisector meets the ray BD at A. Then AC = AD, so AB + AC = AB + AD = BD, and triangle ABC is the required triangle.
Similarly, if the difference AB - AC is given, we mark the difference on the ray from B and use the perpendicular bisector construction again. These constructions show how geometry theorems translate into practical drawing steps.
Constructions are not just an exercise in drawing; they are the practical application of the theorems we have proved. The perpendicular bisector construction uses the fact that the perpendicular bisector of a segment is the set of points equidistant from its endpoints. The angle bisector construction uses the property of points equidistant from the arms of the angle. The triangle constructions apply the congruence criteria, ensuring that the figure we draw is unique and correct. Practising these constructions also improves precision and builds confidence in using the compass and ruler accurately.
| Construction | Key steps |
|---|---|
| Perpendicular bisector of AB | Arcs from A and B, join intersection points |
| Angle bisector | Arcs on arms, then intersecting arcs, join to vertex |
| 60 degree angle | Equilateral triangle construction |
| 90 degree angle | Perpendicular through a point |
| 45 degree angle | Bisect a 90 degree angle |
| Data given | Construction method |
|---|---|
| Three sides | SSS |
| Two sides and included angle | SAS |
| Two angles and included side | ASA |
| Right angle, hypotenuse, one side | RHS |
| Base, base angle, sum of other two sides | Perpendicular bisector of the joining segment |
graph TD
A["Constructions"] --> B["Basic constructions"]
B --> C["Perpendicular bisector"]
B --> D["Angle bisector"]
B --> E["Angles 60, 90, 45 degrees"]
A --> F["Division of line segment"]
F --> G["Divide AB in ratio m:n using parallels"]
A --> H["Triangle constructions"]
H --> I["SSS, SAS, ASA, RHS"]
H --> J["Base, base angle, sum or difference of sides"]
A --> K["Tools"]
K --> L["Compass and unmarked straightedge only"]
In this chapter we learnt the art of geometric construction using only a compass and a straightedge. We constructed the perpendicular bisector of a line segment, the bisector of a given angle, and angles of 60, 90 and 45 degrees. We learnt to divide a line segment in a given ratio using the basic proportionality theorem, and to construct triangles from various given data using the SSS, SAS, ASA and RHS criteria. We also studied the special constructions of triangles when the sum or difference of two sides is given along with the base and base angle. These constructions are not only examination questions themselves; they also reinforce the geometry theorems of the previous chapters and build the practical skills needed for higher-level geometry and drawing work.