Comprehensive theory, key formulas, diagrams, and memory aids for Classical Probability.
Classical probability (also known as theoretical or a priori probability) is the oldest approach to calculating probability. It was developed in the 17th century by mathematicians like Blaise Pascal and Pierre de Fermat to solve problems related to games of chance (such as rolling dice or drawing cards).
The entire foundation of classical probability rests on one crucial assumption: all possible outcomes of an experiment are equally likely. If this assumption holds true, we don't need to perform the experiment hundreds of times to figure out the probability; we can simply calculate it using logic and mathematics.
If a random experiment has $n(S)$ mutually exclusive, exhaustive, and equally likely outcomes, and if $n(E)$ of these outcomes are favorable to an event $E$, then the classical probability of event $E$ occurring is defined as:
$$ P(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{n(E)}{n(S)} $$
Example: Drawing a Card What is the probability of drawing a King from a standard, well-shuffled deck of 52 cards? * Total possible outcomes $n(S) = 52$ (since there are 52 cards). * Favorable outcomes $n(E) = 4$ (since there are 4 Kings in a deck: Hearts, Diamonds, Clubs, Spades). * $P(\text{King}) = \frac{4}{52} = \frac{1}{13}$.
Because the number of favorable outcomes $n(E)$ can never be less than zero, and it can never be greater than the total number of possible outcomes $n(S)$, the probability of any event $E$ must always fall between 0 and 1, inclusive.
$$ 0 \le P(E) \le 1 $$
The bounds of the probability range (0 and 1) represent two extreme types of events.
An event that has absolutely no chance of occurring is called an impossible event. Its subset contains zero sample points ($n(E) = 0$). * Example: Rolling a "7" on a standard six-sided die. Since the faces only go up to 6, $n(\text{Rolling 7}) = 0$. Therefore, $P = \frac{0}{6} = 0$.
An event that is guaranteed to occur is called a certain event. In this case, every possible outcome is a favorable outcome, meaning $n(E) = n(S)$. * Example: Rolling a number less than 10 on a standard six-sided die. Since all faces (1, 2, 3, 4, 5, 6) are less than 10, $n(E) = 6$. Therefore, $P = \frac{6}{6} = 1$.
As we learned in previous topics, the complement of an event $E$ (denoted as $E'$ or $\bar{E}$) consists of all outcomes where event $E$ does not occur.
Because an event and its complement are mutually exclusive and exhaustive, their probabilities must add up to exactly 1 (which represents the entire sample space).
$$ P(E) + P(E') = 1 $$ $$ P(E') = 1 - P(E) $$
Why is this useful? Sometimes, calculating the probability of an event not happening is much mathematically simpler than calculating the probability of it happening.
While classical probability is elegant and foundational, it has strict limitations in the real world:
When approaching classical probability problems, follow these steps: